$(C_2H_5O)_2CO \xrightarrow[H_3O^{+}]{CH_3MgBr(\text{excess})} A$. $A$ (alcohol) can also be obtained by:

  • A
    $CH_3-CH_2-CHO \xrightarrow[H_3O^{+}]{CH_3MgBr(2 \, mol)}$
  • B
    $CH_3-COOC_2H_5 \xrightarrow[H_3O^{+}]{CH_3MgBr(2 \, mol)}$
  • C
    $CH_3-CO-CH_3 \xrightarrow[H_3O^{+}]{CH_3MgBr(1 \, mol)}$
  • D
    as in $(b)$ and $(c)$

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