What are X and Y respectively in the followin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The starting material is $3$-bromobenzoic acid.$1$. Formation of $X$:Reaction with $B_2H_6$ followed by $H_3O^+$ is a selective reduction of the c

Vedclass · Accepted Answer

Vedclass · Answer

(C) The starting material is $3$-bromobenzoic acid.$1$. Formation of $X$:Reaction with $B_2H_6$ followed by $H_3O^+$ is a selective reduction of the carboxylic acid group $(-COOH)$ to a primary alcohol $(-CH_2OH)$ without affecting the bromine $(-Br)$ substituent on the benzene ring. Thus,$X$ is $3$-bromobenzyl alcohol.$2$. Formation of $Y$:$(i)$ Esterification: $3$-bromobenzoic acid reacts with $C_2H_5OH/H^+$ to form ethyl $3$-bromobenzoate.(ii) Reduction: $DIBAL-H$ is a selective reducing agent that reduces esters $(-COOC_2H_5)$ to aldehydes $(-CHO)$.(iii) Hydrolysis: The final step yields $3$-bromobenzaldehyde as $Y$.Therefore,$X$ is $3$-bromobenzyl alcohol and $Y$ is $3$-bromobenzaldehyde. The correct option is $C$.

What are $X$ and $Y$ respectively in the following set of reactions?

Similar Questions

Arrange the following compounds in the correct order of their reactivity towards nucleophilic addition reactions:
$I: CH_3CHO$
$II: CH_3CONH_2$
$III: HCHO$
$IV: CH_3COCH_3$

The amount (in $mol$) of bromoform $(CHBr_{3})$ produced when $1.0 \ mol$ of acetone reacts completely with $1.0 \ mol$ of bromine in the presence of aqueous $NaOH$ is $......$

$A$ carbonyl compound $X$ $(C_8H_8O)$ undergoes disproportionation with conc. $KOH$ on heating. The product of $X$ with $Zn-Hg/HCl$ is $Y$ and the product of $X$ with $NaBH_4$ is $Z$. What are $Y$ and $Z$ respectively?

The product $(A)$ of the reaction is:

The intermediate $J$ in the following Wittig reaction is

Vedclass Test Series

Exam Paper Generator

Online Exam Module