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(C) $LiAlH_4$ is a strong reducing agent that reduces esters and anhydrides to primary alcohols. In the given molecule,there is an ester group $(-COOC

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(C) $LiAlH_4$ is a strong reducing agent that reduces esters and anhydrides to primary alcohols. In the given molecule,there is an ester group $(-COOCH_3)$ and an anhydride-like linkage. Upon treatment with $LiAlH_4$ followed by $H_2O$,the ester group is reduced to a primary alcohol $(-CH_2OH)$ and the anhydride linkage is cleaved to form a secondary alcohol $(-OH)$ at the same carbon atom,along with the release of methanol $(CH_3OH)$ and ethanol $(CH_3CH_2OH)$. The final product $(A)$ is a cyclic diol containing both a tertiary hydroxyl group and a primary hydroxymethyl group at the same carbon position.

The product $(A)$ of the reaction is:

Similar Questions

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The product of the given reaction is:

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