A and B in the following reaction are: | vedclass

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(A) The reaction of $2$-substituted cyclohexanone with $KMnO_4$ involves oxidative cleavage of the ring.$KMnO_4$ acts as a strong oxidizing agent that

Vedclass · Accepted Answer

$A = R-CO-(CH_2)_4-COOH$,$B = R-(CH_2)_5-COOH$

Vedclass · Answer

(A) The reaction of $2$-substituted cyclohexanone with $KMnO_4$ involves oxidative cleavage of the ring.$KMnO_4$ acts as a strong oxidizing agent that cleaves the $C-C$ bond adjacent to the carbonyl group,resulting in the formation of a keto-acid,$R-CO-(CH_2)_4-COOH$ (which is $A$).Subsequently,the Wolff-Kishner reduction,using $NH_2NH_2$ and $KOH$ followed by $H_3O^+$,reduces the carbonyl group $(C=O)$ to a methylene group $(-CH_2-)$.Therefore,the final product $B$ is $R-CH_2-(CH_2)_4-COOH$,which is $R-(CH_2)_5-COOH$.

List-$I$	List-$II$
$1.$ Ammoniacal $AgNO_3$	$a.$ Primary amine
$2.$ $HIO_4$	$b.$ Aldehyde
$3.$ Alkaline $KMnO_4$	$c.$ Vicinal-$OH$
$4.$ Chloroform $NaOH$	$d.$ Double bond

$A$ and $B$ in the following reaction are:

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Match List-$I$ with List-$II$.
List-$I$ List-$II$
$1.$ Ammoniacal $AgNO_3$ $a.$ Primary amine
$2.$ $HIO_4$ $b.$ Aldehyde
$3.$ Alkaline $KMnO_4$ $c.$ Vicinal-$OH$
$4.$ Chloroform $NaOH$ $d.$ Double bond

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