S_{N}1 and S_{N}2 products are the same (excl | vedclass

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Question

(C) $S_{N}1$ reactions involve the formation of a carbocation intermediate,which can undergo rearrangement if a more stable carbocation can be formed.

Vedclass · Accepted Answer

$4-$methylchlorocyclohexane

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(C) $S_{N}1$ reactions involve the formation of a carbocation intermediate,which can undergo rearrangement if a more stable carbocation can be formed. $S_{N}2$ reactions occur in a single step with inversion of configuration and no rearrangement. For the products to be the same (excluding stereoisomers),the substrate must not undergo rearrangement during the $S_{N}1$ process. In $4$-methylchlorocyclohexane,the chlorine is attached to a secondary carbon. Upon ionization,it forms a secondary carbocation that does not rearrange to a more stable form,leading to the same substitution product as the $S_{N}2$ pathway.

$S_{N}1$ and $S_{N}2$ products are the same (excluding stereoisomers) for which of the following compounds?

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