HC equiv CNa + Cl - CH_2 - CH_2 - CH_2 - I to | vedclass

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(C) The reaction involves the nucleophilic substitution of an alkyl halide by an acetylide ion $(HC \equiv C^-)$.In the substrate $Cl - CH_2 - CH_2 -

Vedclass · Accepted Answer

$H - C \equiv C - CH_2 - CH_2 - CH_2 - Cl$

Vedclass · Answer

(C) The reaction involves the nucleophilic substitution of an alkyl halide by an acetylide ion $(HC \equiv C^-)$.In the substrate $Cl - CH_2 - CH_2 - CH_2 - I$,there are two halogen atoms: chlorine $(-Cl)$ and iodine $(-I)$.Iodide $(I^-)$ is a much better leaving group than chloride $(Cl^-)$ due to its larger size and weaker $C-I$ bond compared to the $C-Cl$ bond.Therefore,the nucleophilic attack by the acetylide ion occurs preferentially at the carbon atom attached to the iodine atom via an $S_N2$ mechanism.The major product is $H - C \equiv C - CH_2 - CH_2 - CH_2 - Cl$.

$HC \equiv CNa + Cl - CH_2 - CH_2 - CH_2 - I \to (A)$; Major product $(A)$ is

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