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(A) The hydration of propyne $(CH_3-C \equiv CH)$ in the presence of $H_2SO_4$ and $HgSO_4$ follows Markovnikov's addition of water across the triple

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Acetone

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(A) The hydration of propyne $(CH_3-C \equiv CH)$ in the presence of $H_2SO_4$ and $HgSO_4$ follows Markovnikov's addition of water across the triple bond.First,an unstable enol intermediate $(CH_3-C(OH)=CH_2)$ is formed.This enol undergoes tautomerization to form a stable ketone.Reaction: $CH_3-C \equiv CH + H_2O \xrightarrow{H_2SO_4, HgSO_4} CH_3-C(OH)=CH_2 \rightleftharpoons CH_3-CO-CH_3$ (Acetone).

What is the product formed by the hydration of propyne in the presence of $H_2SO_4$ and $HgSO_4$?

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