Br-CH_2-CH=CH-CH_2-Br xrightarrow{Zn (dust)} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction of $1,4$-dibromobut$-2-$ene with $Zn$ dust involves the removal of two bromine atoms from the $1$ and $4$ positions.This process is k

Vedclass · Accepted Answer

$H_2C=CH-CH=CH_2$

Vedclass · Answer

(D) The reaction of $1,4$-dibromobut$-2-$ene with $Zn$ dust involves the removal of two bromine atoms from the $1$ and $4$ positions.This process is known as $1,4$-elimination.The mechanism involves the formation of a cyclic transition state or an organozinc intermediate,leading to the formation of a conjugated diene.The product formed is $1,3$-butadiene,which has the structure $H_2C=CH-CH=CH_2$.

$Br-CH_2-CH=CH-CH_2-Br \xrightarrow{Zn (dust)} (A)$
Above reaction is an example of $1,4$-elimination. Predict the product.

Similar Questions

$trans$-cyclohexane-$1,2$-diol can be obtained by the reaction of cyclohexene with

Product $(A)$ will be

The compound formed by passing ethylene gas into a cold alkaline solution of $KMnO_4$ is:

An unsaturated organic compound,$X$ on reaction with hot,acidified $KMnO_4$ gives succinic acid. What is $X$?

What is hydrogenation reaction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$Br-CH_2-CH=CH-CH_2-Br \xrightarrow{Zn (dust)} (A)$Above reaction is an example of $1,4$-elimination. Predict the product.