underset{(text{Calcium carbide})}{CaC_2} xrig | vedclass

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Question

(C) $1$. Calcium carbide $(CaC_2)$ reacts with water $(H_2O)$ to produce acetylene $(C_2H_2)$,which is compound $(A)$.$CaC_2 + 2H_2O \rightarrow Ca(OH

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Benzene

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(C) $1$. Calcium carbide $(CaC_2)$ reacts with water $(H_2O)$ to produce acetylene $(C_2H_2)$,which is compound $(A)$.$CaC_2 + 2H_2O ightarrow Ca(OH)_2 + C_2H_2 (A)$$2$. When acetylene $(C_2H_2)$ is passed through a red-hot copper tube at high temperature,it undergoes cyclic polymerization to form benzene $(C_6H_6)$,which is compound $(B)$.$3C_2H_2 \xrightarrow{	ext{Red hot Cu tube}} C_6H_6 (B)$$3$. Therefore,the product $(B)$ is Benzene.

$\underset{(\text{Calcium carbide})}{CaC_2}$ $\xrightarrow{H_2O} (A)$ $\xrightarrow{\text{Red hot Cu tube}} (B)$. The product $(B)$ of the reaction is:

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