$Ph-CH_2-CH=CH-CH_3$ $\xrightarrow[(ii) \text{ Alc. KOH}]{(i) \text{ } Br_2}$ ?

  • A
    $Ph-CH=CH-CH=CH_2$
  • B
    $Ph-CH_2-CH(OH)-CH(OH)-CH_3$
  • C
    $Ph-CH_2-C \equiv C-CH_3$
  • D
    $Ph-C \equiv C-CH_2-CH_3$

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