CH_3-CH_2-CH_2-C equiv CH xrightarrow[text{Ex | vedclass

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(B) The reaction of $pent-1-yne$ with excess $HCl$ follows Markovnikov's rule.In the first step,$HCl$ adds to the triple bond to form a geminal-like i

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$CH_3-CH_2-CH_2-CCl_2-CH_3$

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(B) The reaction of $pent-1-yne$ with excess $HCl$ follows Markovnikov's rule.In the first step,$HCl$ adds to the triple bond to form a geminal-like intermediate,but specifically,the $Cl$ atom attaches to the more substituted carbon (the $C-2$ position).$CH_3-CH_2-CH_2-C \equiv CH + HCl \rightarrow CH_3-CH_2-CH_2-CCl=CH_2$In the second step,another molecule of $HCl$ adds to the double bond,again following Markovnikov's rule,resulting in the formation of a geminal dichloride at the $C-2$ position.$CH_3-CH_2-CH_2-CCl=CH_2 + HCl \rightarrow CH_3-CH_2-CH_2-CCl_2-CH_3$.

$CH_3-CH_2-CH_2-C \equiv CH \xrightarrow[\text{Excess}]{HCl} ?$

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