$(EtO)_2CH-CHO + CH_3MgI \xrightarrow{H_3O^{+}} (A)$. The product obtained in the above reaction is:

  • A
    $CH_3-CO-CHO$
  • B
    $CH_3-CH(OH)-CHO$
  • C
    $CH_3-CO-CH_2OH$
  • D
    $CH_3-CH(OH)-CH_2OH$

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