C_6H_6O (phenol) xrightarrow[text{3}H_2text{ | vedclass

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(B) The reaction sequence is as follows:$1$. Phenol $(C_6H_6O)$ undergoes catalytic hydrogenation with $H_2/Ni$ to form cyclohexanol $(A)$.$2$. Cycloh

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Nylon $6$

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(B) The reaction sequence is as follows:$1$. Phenol $(C_6H_6O)$ undergoes catalytic hydrogenation with $H_2/Ni$ to form cyclohexanol $(A)$.$2$. Cyclohexanol $(A)$ is oxidized using $Cu$ (dehydrogenation) to form cyclohexanone $(B)$.$3$. Cyclohexanone $(B)$ reacts with hydroxylamine $(NH_2OH)$ to form cyclohexanone oxime $(C)$.$4$. Cyclohexanone oxime $(C)$ undergoes Beckmann rearrangement in the presence of acid $(H^+)$ to form caprolactam $(D)$.$5$. Caprolactam $(D)$ undergoes ring-opening polymerization in the presence of base $(HO^-)$ to form Nylon $6$ $(E)$.

$C_6H_6O$ (phenol) $\xrightarrow[\text{3}H_2\text{ (High temp and pressure)}]{Ni} (A)$ $\xrightarrow{Cu} (B)$ $\xrightarrow{NH_2OH} (C)$ $\xrightarrow{H^{+}} (D)$ $\xrightarrow{HO^{-}} (E)$
Product $(E)$ is

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$C_6H_6O$ (phenol) $\xrightarrow[\text{3}H_2\text{ (High temp and pressure)}]{Ni} (A)$ $\xrightarrow{Cu} (B)$ $\xrightarrow{NH_2OH} (C)$ $\xrightarrow{H^{+}} (D)$ $\xrightarrow{HO^{-}} (E)$Product $(E)$ is