In the given reaction sequence,identify the f | vedclass

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(C) The reaction sequence is as follows:Step $1$: Phenol reacts with $OH^-$ followed by $CO_2$ and $H^+$ (Kolbe-Schmitt reaction) to form Salicylic ac

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$2-$Acetoxybenzoic acid

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(C) The reaction sequence is as follows:Step $1$: Phenol reacts with $OH^-$ followed by $CO_2$ and $H^+$ (Kolbe-Schmitt reaction) to form Salicylic acid $(A)$,which is $2$-hydroxybenzoic acid.Step $2$: Salicylic acid reacts with acetyl chloride $(CH_3COCl)$ in the presence of pyridine (acetylation). The phenolic $-OH$ group is acetylated to form Acetylsalicylic acid (Aspirin),which is $2$-acetoxybenzoic acid.The structure of $2$-acetoxybenzoic acid is a benzene ring with a $-COOH$ group at the ortho position and an $-OCOCH_3$ group at the other ortho position (relative to the original $-OH$ position).

In the given reaction sequence,identify the final product $B$:
Phenol $\xrightarrow[(2) CO_2]{(1) OH^-} A$ $\xrightarrow[Pyridine]{CH_3COCl} B$

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In the given reaction sequence,identify the final product $B$:Phenol $\xrightarrow[(2) CO_2]{(1) OH^-} A$ $\xrightarrow[Pyridine]{CH_3COCl} B$