Identify the product Z in the following react | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. The reaction of aniline with acetyl chloride $(CH_3COCl)$ is an acetylation reaction,which protects the amino group to form $X$,which is acet

Vedclass · Accepted Answer

p-Bromoaniline

Vedclass · Answer

(A) $1$. The reaction of aniline with acetyl chloride $(CH_3COCl)$ is an acetylation reaction,which protects the amino group to form $X$,which is acetanilide $(C_6H_5NHCOCH_3)$.$2$. Acetanilide $(X)$ undergoes electrophilic aromatic substitution with $Br_2/AlBr_3$. The acetamido group $(-NHCOCH_3)$ is ortho/para directing. Due to steric hindrance,the para-substituted product $Y$ (p-bromoacetanilide) is the major product.$3$. Finally,the hydrolysis of $Y$ with $H_3O^+$ removes the acetyl protecting group to regenerate the amino group,yielding $Z$,which is p-bromoaniline.

Identify the product $Z$ in the following reaction sequence:
Aniline $\xrightarrow{CH_3COCl} X$ $\xrightarrow{Br_2/AlBr_3} Y$ $\xrightarrow{H_3O^+} Z$

Similar Questions

Aniline $\xrightarrow[{{0^{\circ}}C - {5^{\circ}}C}]{{NaNO_2/HCl}}A$ $\xrightarrow{{Ph-N(CH_3)_2}}B$
What is $B$?

Carbylamine is formed from aliphatic or aromatic primary amine via which of the following intermediates?

Which of the following compounds acts as the strongest base in its aqueous solution?

Consider the following reaction sequence and identify the correct option:

In the reaction $C_6H_5CHO + C_6H_5NH_2 \to C_6H_5N=CHC_6H_5 + H_2O$,the compound $C_6H_5N=CHC_6H_5$ is known as

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Identify the product $Z$ in the following reaction sequence:Aniline $\xrightarrow{CH_3COCl} X$ $\xrightarrow{Br_2/AlBr_3} Y$ $\xrightarrow{H_3O^+} Z$