$CaCl_2$ is preferred over $NaCl$ for clearing ice on roads,particularly in very cold countries. This is because:
- A$CaCl_2$ is less soluble in $H_2O$ than $NaCl$
- B$CaCl_2$ is hygroscopic but $NaCl$ is not
- CEutectic mixture of $CaCl_2/H_2O$ freezes at $-55 \ ^oC$ while that of $NaCl/H_2O$ freezes at $-18 \ ^oC$
- D$NaCl$ makes the road slippery but $CaCl_2$ does not
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