Cl_{2(g)} + Ba(OH)_2 to X (aq.) + BaCl_2 + H_ | vedclass

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(B) The reaction of chlorine with barium hydroxide is: $6Cl_2 + 6Ba(OH)_2 	o Ba(ClO_3)_2 (X) + 5BaCl_2 + 6H_2O$.When $X$ $(Ba(ClO_3)_2)$ reacts with

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$HClO_3, ClO_2$

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(B) The reaction of chlorine with barium hydroxide is: $6Cl_2 + 6Ba(OH)_2 	o Ba(ClO_3)_2 (X) + 5BaCl_2 + 6H_2O$.When $X$ $(Ba(ClO_3)_2)$ reacts with $H_2SO_4$,it forms chloric acid $(Y)$:$Ba(ClO_3)_2 + H_2SO_4 	o 2HClO_3 (Y) + BaSO_4 \downarrow$.Chloric acid $(HClO_3)$ decomposes upon heating above $365 \ K$ to produce chlorine dioxide $(Z)$:$2HClO_3 \xrightarrow{\Delta > 365 \ K} 2ClO_2 (Z) + H_2O + \frac{1}{2} O_2$.Thus,$Y$ is $HClO_3$ and $Z$ is $ClO_2$.

$Cl_{2(g)} + Ba(OH)_2 \to X (aq.) + BaCl_2 + H_2O$
$X + H_2SO_4 \to Y + BaSO_4$
$Y \xrightarrow[\Delta > 365 \ K]{\Delta } Z + H_2O + O_2$
$Y$ and $Z$ are respectively

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$Cl_{2(g)} + Ba(OH)_2 \to X (aq.) + BaCl_2 + H_2O$$X + H_2SO_4 \to Y + BaSO_4$$Y \xrightarrow[\Delta > 365 \ K]{\Delta } Z + H_2O + O_2$$Y$ and $Z$ are respectively