3NaClO xrightarrow{Delta} NaClO_3 + 2NaClWhic | vedclass

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(D) In the reaction $3NaClO \xrightarrow{\Delta} NaClO_3 + 2NaCl$,the oxidation state of $Cl$ in $NaClO$ is $+1$.In $NaClO_3$,the oxidation state of $

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(D) In the reaction $3NaClO \xrightarrow{\Delta} NaClO_3 + 2NaCl$,the oxidation state of $Cl$ in $NaClO$ is $+1$.In $NaClO_3$,the oxidation state of $Cl$ is $+5$ (increase).In $NaCl$,the oxidation state of $Cl$ is $-1$ (decrease).Since the oxidation state of the same element $(Cl)$ both increases and decreases,it is a disproportionation reaction.This method is commonly used for the preparation of chlorates (a type of halate).

$3NaClO \xrightarrow{\Delta} NaClO_3 + 2NaCl$
Which of the following is true for the given reaction?

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$3NaClO \xrightarrow{\Delta} NaClO_3 + 2NaCl$Which of the following is true for the given reaction?