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(A) According to de Broglie's hypothesis,the wavelength $\lambda$ is given by $\lambda = h/mv$. For a particle moving with velocity $v$,the phase velo

Vedclass · Accepted Answer

$c^2/v$

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(A) According to de Broglie's hypothesis,the wavelength $\lambda$ is given by $\lambda = h/mv$. For a particle moving with velocity $v$,the phase velocity (or wave velocity) $u$ of the associated de Broglie wave is given by $u = E/p$,where $E$ is the total energy and $p$ is the momentum. Using Einstein's mass-energy relation $E = mc^2$ and momentum $p = mv$,we get $u = (mc^2)/(mv) = c^2/v$. Thus,the velocity of the de Broglie wave is $c^2/v$.

The velocity of a de Broglie wave is represented by which of the following expressions?

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