In how many grams of CO_2 is the number of C | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The number of moles of $C$ atoms is given by $n = \frac{1.3699 	imes 10^{23}}{6.022 	imes 10^{23}} = 0.2275 \ mol$.Since one molecule of $CO_2$

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(D) The number of moles of $C$ atoms is given by $n = \frac{1.3699 	imes 10^{23}}{6.022 	imes 10^{23}} = 0.2275 \ mol$.Since one molecule of $CO_2$ contains one $C$ atom,the moles of $CO_2$ are equal to the moles of $C$ atoms,which is $0.2275 \ mol$.The molar mass of $CO_2$ is $44 \ g/mol$.Mass of $CO_2 = 	ext{moles} 	imes 	ext{molar mass} = 0.2275 \ mol 	imes 44 \ g/mol = 10 \ g$.

In how many grams of $CO_2$ is the number of $C$ atoms equal to $1.3699 \times 10^{23}$?

Similar Questions

What is the mole fraction of oxygen in a mixture of $7 \ g$ of nitrogen and $8 \ g$ of oxygen?

The number of gram-molecules of $SO_2Cl_2$ in $13.5 \ g$ of sulfuryl chloride is .............

If $10^{21}$ molecules are removed from $200 \ mg$ of $CO_2$,how many moles of $CO_2$ will remain?

What is the number of atoms in $280 \ g$ of $Fe$?

What is the number of atoms present in $16 \ g$ of oxygen gas $(O_2)$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module