At STP,2.8 , L of a gaseous substance weighs | vedclass

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(A) $1$. Calculate the molar mass of the gas: At $STP$,$22.4 \, L$ of any gas contains $1 \, mole$. $2$. Given $2.8 \, L$ weighs $5.5 \, g$,so $22.4 \

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$N_2O$

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(A) $1$. Calculate the molar mass of the gas: At $STP$,$22.4 \, L$ of any gas contains $1 \, mole$. $2$. Given $2.8 \, L$ weighs $5.5 \, g$,so $22.4 \, L$ will weigh $(5.5 / 2.8) 	imes 22.4 = 44 \, g/mol$. $3$. Check the molar masses of the options: $N_2O = (2 	imes 14) + 16 = 44 \, g/mol$. $N_2O_5 = (2 	imes 14) + (5 	imes 16) = 108 \, g/mol$. $NO_2 = 14 + (2 	imes 16) = 46 \, g/mol$. $N_2O_3 = (2 	imes 14) + (3 	imes 16) = 76 \, g/mol$. $4$. Since the molar mass is $44 \, g/mol$,the correct formula is $N_2O$.

At $STP$,$2.8 \, L$ of a gaseous substance weighs $5.5 \, g$. If the compound contains $N$ and $O$ atoms,its molecular formula will be ..............

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