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(A) According to Avogadro's Law,at the same temperature and pressure,equal volumes of gases contain an equal number of moles.Since the volumes are equ

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$C_3H_8$

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(A) According to Avogadro's Law,at the same temperature and pressure,equal volumes of gases contain an equal number of moles.Since the volumes are equal ($3 \ L$ each),the number of moles of the hydrocarbon $(n_H)$ and $CO_2$ $(n_{CO_2})$ are equal.$n_H = n_{CO_2}$Given that the masses $(w)$ are also equal,the molar mass $(M)$ must be equal:$\frac{w}{M_H} = \frac{w}{M_{CO_2}}$$M_H = M_{CO_2}$The molar mass of $CO_2 = 12 + (2 	imes 16) = 44 \ g/mol$.Therefore,the molar mass of the hydrocarbon is $44 \ g/mol$.For $C_3H_8$: $M = (3 	imes 12) + (8 	imes 1) = 36 + 8 = 44 \ g/mol$.Thus,the hydrocarbon is $C_3H_8$.

At the same temperature and pressure,if the mass of $3 \ L$ of a hydrocarbon is equal to the mass of $3 \ L$ of $CO_2$,what is the molecular formula of the hydrocarbon?

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