(A) The general combustion reaction for a hydrocarbon $C_xH_y$ is: $C_xH_y + (x + y/4)O_2 \rightarrow xCO_2 + (y/2)H_2O$. For the hydrocarbon $C_xH_{2

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(A) The general combustion reaction for a hydrocarbon $C_xH_y$ is: $C_xH_y + (x + y/4)O_2 \rightarrow xCO_2 + (y/2)H_2O$. For the hydrocarbon $C_xH_{2n-2}$,we have $y = 2n - 2$. Substituting $y$ into the coefficients: Coefficient of $CO_2 = x$. Coefficient of $H_2O = y/2 = (2n - 2)/2 = n - 1$. Coefficient of $O_2 = x + y/4 = x + (2n - 2)/4 = x + (n - 1)/2$. Thus,the coefficients are $x + (n - 1)/2, x, n - 1$.

Class 11 Chemistry Some Basic Concepts of Chemistry Chemical stoichiometry

Medium

In the balanced combustion reaction of $1 \, mol$ of $C_xH_{2n-2}$ hydrocarbon,the coefficients of $O_2$,$CO_2$,and $H_2O$ will be respectively ...

A
$x + (n - 1)/2, x, n - 1$
B
$x + (2n - 2), x, n/2$
C
$x + 2n, x, n/4$
D
$x + (n - 1)/4, x, 2n - 2$

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Class 11

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Some Basic Concepts of Chemistry

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Chemical stoichiometry

If $2 \ g$ of $NaOH$ is dissolved in water to make a $100 \ cm^3$ solution,what is the normality of this solution?

Medium

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EasyTS EAMCET 2011

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$KMnO_4$ reacts with oxalic acid according to the equation,$2MnO_4^- + 5C_2O_4^{2-} + 16H^{+} \to 2Mn^{2+} + 10CO_2 + 8H_2O$. Here,$20 \ mL$ of $0.1 \ M$ $KMnO_4$ is equivalent to:

MediumAIPMT 1996

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$18 \ L$ mixture of $N_2$ and $H_2$ gives maximum $6 \ L$ of $NH_3$ at same temperature and pressure. What will be the ratio of $N_2$ and $H_2$ initially taken?

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What is the weight in $g$ of potassium chlorate $(KClO_3)$ required to produce the oxygen needed for the complete combustion of $84 \ L$ of $CO$ at $N.T.P$?

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In the balanced combustion reaction of $1 \, mol$ of $C_xH_{2n-2}$ hydrocarbon,the coefficients of $O_2$,$CO_2$,and $H_2O$ will be respectively ...

Similar Questions

If $2 \ g$ of $NaOH$ is dissolved in water to make a $100 \ cm^3$ solution,what is the normality of this solution?

The volume in $mL$ of $0.1 \ M$ solution of $NaOH$ required to completely neutralize $100 \ mL$ of $0.3 \ M$ solution of $H_3PO_3$ is

$KMnO_4$ reacts with oxalic acid according to the equation,$2MnO_4^- + 5C_2O_4^{2-} + 16H^{+} \to 2Mn^{2+} + 10CO_2 + 8H_2O$. Here,$20 \ mL$ of $0.1 \ M$ $KMnO_4$ is equivalent to:

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