When equal volumes of 0.1 , M , AgNO_3 and 0. | vedclass

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(B) The $NO_3^-$ ions are provided only by the $AgNO_3$ solution.Since equal volumes of both solutions are mixed,the total volume becomes double the i

Vedclass · Accepted Answer

$0.05$

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(B) The $NO_3^-$ ions are provided only by the $AgNO_3$ solution.Since equal volumes of both solutions are mixed,the total volume becomes double the initial volume of each solution.Let the volume of each solution be $V$. The total volume of the mixture is $2V$.The number of moles of $NO_3^-$ is equal to the number of moles of $AgNO_3$,which is $0.1 	imes V$.The concentration of $NO_3^-$ in the mixture is given by:$[NO_3^-] = \frac{	ext{moles of } NO_3^-}{	ext{total volume}} = \frac{0.1 	imes V}{2V} = 0.05 \, M$.

When equal volumes of $0.1 \, M \, AgNO_3$ and $0.2 \, M \, NaCl$ are mixed,the concentration of $NO_3^-$ in the resulting mixture will be .......... $M$.

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