If the mole fraction of the solute in liquid | vedclass

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(C) The formula for molality $(m)$ in terms of mole fraction is given by: $m = \frac{1000 	imes X_2}{M_1 	imes X_1}$.Here,$X_2$ (mole fraction of so

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$1.95$

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(C) The formula for molality $(m)$ in terms of mole fraction is given by: $m = \frac{1000 	imes X_2}{M_1 	imes X_1}$.Here,$X_2$ (mole fraction of solute) $= 0.2$,so $X_1$ (mole fraction of solvent) $= 1 - 0.2 = 0.8$.The molar mass of naphthalene $(C_{10}H_{8})$ is $M_1 = (10 	imes 12) + (8 	imes 1) = 128 \ g/mol$.Substituting the values: $m = \frac{1000 	imes 0.2}{128 	imes 0.8}$.$m = \frac{200}{102.4} = 1.953 \ m \approx 1.95 \ m$.

If the mole fraction of the solute in liquid naphthalene $(C_{10}H_{8})$ is $0.2$,then the molality of the solution will be ............ $m$.

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