Which of the following bonds is the most pola | vedclass

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(B) The polarity of a bond depends on the difference in electronegativity between the two bonded atoms. The greater the difference in electronegativit

Vedclass · Accepted Answer

$C - F$

Vedclass · Answer

(B) The polarity of a bond depends on the difference in electronegativity between the two bonded atoms. The greater the difference in electronegativity,the more polar the bond.Using the Pauling scale,the electronegativity values are: $C = 2.55$,$O = 3.44$,$N = 3.04$,and $F = 3.98$.The differences in electronegativity are:$C - O: |3.44 - 2.55| = 0.89$$C - F: |3.98 - 2.55| = 1.43$$O - F: |3.98 - 3.44| = 0.54$$N - F: |3.98 - 3.04| = 0.94$Comparing these values,the $C - F$ bond has the largest electronegativity difference,making it the most polar bond.

Which of the following bonds is the most polar?

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