The Delta H^o of combustion of C_4H_{10(g)} i | vedclass

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(C) The molar mass of $C_4H_{10}$ is $(4 	imes 12) + (10 	imes 1) = 58 \ g \ mol^{-1}$.The number of moles in $5.8 \ kg$ $(5800 \ g)$ of $C_4H_{10}$

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$2.65 	imes 10^5 \ kJ$

Vedclass · Answer

(C) The molar mass of $C_4H_{10}$ is $(4 	imes 12) + (10 	imes 1) = 58 \ g \ mol^{-1}$.The number of moles in $5.8 \ kg$ $(5800 \ g)$ of $C_4H_{10}$ is calculated as:$n = \frac{5800 \ g}{58 \ g \ mol^{-1}} = 100 \ mol$.The heat evolved at constant pressure is given by $q = n 	imes |\Delta H^o_{comb}|$.$q = 100 \ mol 	imes 2650 \ kJ \ mol^{-1} = 265,000 \ kJ = 2.65 	imes 10^5 \ kJ$.

The $\Delta H^o$ of combustion of $C_4H_{10(g)}$ is $-2650 \ kJ \ mol^{-1}$. The amount of heat evolved at constant pressure that can be obtained by burning $5.8 \ kg$ of $C_4H_{10}$ is approximately:

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