$PtCl_4 \cdot 6H_2O$ can exist as a hydrated complex. Its $1 \ m$ aqueous solution has a depression in freezing point of $3.72 \ ^\circ C$. Assuming $100\%$ ionization and $K_f \ (H_2O) = 1.86 \ ^\circ C \ kg \ mol^{-1}$,the correct formula for the complex is:

  • A
    $[Pt(H_2O)_6]Cl_4$
  • B
    $[Pt(H_2O)_4Cl_2]Cl_2 \cdot 2H_2O$
  • C
    $[Pt(H_2O)_3Cl_3]Cl \cdot 3H_2O$
  • D
    $[Pt(H_2O)_2Cl_4] \cdot 4H_2O$

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