CHO-(CHOH)_4-CH_2OH xrightarrow{Br_2/H_2O} P; | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Bromine water $(Br_2/H_2O)$ is a mild oxidizing agent.It selectively oxidizes the aldehyde group $(-CHO)$ of glucose to a carboxylic acid group $(

Vedclass · Accepted Answer

$COOH-(CHOH)_4-CH_2OH$

Vedclass · Answer

(A) Bromine water $(Br_2/H_2O)$ is a mild oxidizing agent.It selectively oxidizes the aldehyde group $(-CHO)$ of glucose to a carboxylic acid group $(-COOH)$.This reaction results in the formation of gluconic acid,which is represented by the formula $COOH-(CHOH)_4-CH_2OH$.It does not oxidize the primary or secondary alcohol groups present in the molecule.

$CHO-(CHOH)_4-CH_2OH \xrightarrow{Br_2/H_2O} P$; $P$ is:

Similar Questions

Which monosaccharide units are present in starch,cellulose,and glucose,and which linkages connect these units?

$D-(+)$-glucose reacts with hydroxylamine and yields an oxime. The structure of the oxime would be:

Which one of the following compounds will form an osazone derivative?

Glucose $\xrightarrow{HCN} A$ $\xrightarrow{Hydrolysis} B$ $\xrightarrow{HI, \Delta} C$. What is the final product $C$?

For the below given cyclic hemiacetal $(X)$,the correct pyranose structure is.

Vedclass Test Series

Exam Paper Generator

Online Exam Module