The EN (Electronegativity) of element A is E_ | vedclass

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Question

(A) According to the Mulliken scale,the electronegativity $(EN)$ of an element is the average of its ionization potential $(IP)$ and electron affinity

Vedclass · Accepted Answer

$2E_1 - E_2$

Vedclass · Answer

(A) According to the Mulliken scale,the electronegativity $(EN)$ of an element is the average of its ionization potential $(IP)$ and electron affinity $(EA)$.The formula is given by: $EN = \frac{IP + EA}{2}$.Given that $EN = E_1$ and $IP = E_2$,we substitute these values into the formula:$E_1 = \frac{E_2 + EA}{2}$.Multiplying both sides by $2$ gives:$2E_1 = E_2 + EA$.Rearranging to solve for $EA$:$EA = 2E_1 - E_2$.

The $EN$ (Electronegativity) of element $A$ is $E_1$ and its $IP$ (Ionization Potential) is $E_2$. Hence,the $EA$ (Electron Affinity) will be:

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