Which of the following complexes exhibits $dsp^2$ hybridization?

  • A
    $[NiCl_4]^{2-}$
  • B
    $[Ni(CN)_4]^{2-}$
  • C
    $[Zn(NH_3)_4]^{2+}$
  • D
    $[FeF_6]^{3-}$

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The pair$(s)$ of complexes wherein both exhibit tetrahedral geometry is(are):
Note: $py = \text{pyridine}$
Given: Atomic numbers of $Fe, Co, Ni$ and $Cu$ are $26, 27, 28$ and $29$,respectively.
$(A)$ $[FeCl_4]^-$ and $[Fe(CO)_4]^{2-}$
$(B)$ $[Co(CO)_4]^-$ and $[CoCl_4]^{2-}$
$(C)$ $[Ni(CO)_4]$ and $[Ni(CN)_4]^{2-}$
$(D)$ $[Cu(py)_4]^+$ and $[Cu(CN)_4]^{3-}$

Considering that $\Delta_{0} > P$,the magnetic moment (in $BM$) of $[Ru(H_{2}O)_{6}]^{2+}$ would be

Match the hybridisation in Column $I$ with the complexes in Column $II$. The options represent the matches for $(A), (B), (C), (D)$ respectively.
Column $I$Column $II$
$(A)$ $sp^3$$(i)$ $[Co(NH_3)_6]^{3+}$
$(B)$ $dsp^2$$(ii)$ $[Ni(CO)_4]$
$(C)$ $sp^3d^2$$(iii)$ $[Pt(NH_3)_2Cl_2]$
$(D)$ $d^2sp^3$$(iv)$ $[CoF_6]^{3-}$
$(v)$ $[Fe(CO)_5]$

Both $[Ni(CO)_4]$ and $[Ni(CN)_4]^{2-}$ are diamagnetic. The hybridization of nickel in these complexes,respectively,are

Which of the following matches is incorrect?
Complex compounds $-$ Type of hybridization

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