(A) In $[Cr(NH_3)_6]^{3+}$,the oxidation state of $Cr$ is $+3$. The electronic configuration of $Cr$ $(Z=24)$ is $[Ar] 3d^5 4s^1$. Thus,$Cr^{3+}$ is $

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(A) In $[Cr(NH_3)_6]^{3+}$,the oxidation state of $Cr$ is $+3$. The electronic configuration of $Cr$ $(Z=24)$ is $[Ar] 3d^5 4s^1$. Thus,$Cr^{3+}$ is $[Ar] 3d^3$. Since there are $3$ unpaired electrons in the $3d$ orbitals,the complex is paramagnetic. The geometry is octahedral due to $d^2sp^3$ hybridization.

Class 12 Chemistry Coordination Compounds Isomerism and Magnetic properties

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The $[Cr(NH_3)_6]^{3+}$ ion is ...

A
Paramagnetic
B
Diamagnetic
C
Square planar
D
None of these

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Isomerism and Magnetic properties

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The $[Cr(NH_3)_6]^{3+}$ ion is ...

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