Which of the following ions is paramagnetic?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine if a complex is paramagnetic,we check for the presence of unpaired electrons in the metal ion.$1$. In $[Ni(H_2O)_6]^{2+}$,$Ni$ is in

Vedclass · Accepted Answer

$[Ni(H_2O)_6]^{2+}$

Vedclass · Answer

(A) To determine if a complex is paramagnetic,we check for the presence of unpaired electrons in the metal ion.$1$. In $[Ni(H_2O)_6]^{2+}$,$Ni$ is in the $+2$ oxidation state $(3d^8)$. $H_2O$ is a weak field ligand,so the electrons remain unpaired,resulting in $2$ unpaired electrons. Thus,it is paramagnetic.$2$. In $[Fe(CN)_6]^{4-}$,$Fe$ is in the $+2$ oxidation state $(3d^6)$. $CN^-$ is a strong field ligand,causing pairing of electrons,resulting in $0$ unpaired electrons. It is diamagnetic.$3$. In $[Ni(CO)_4]$,$Ni$ is in the $0$ oxidation state $(3d^8 4s^2)$. $CO$ is a strong field ligand,causing pairing,resulting in $0$ unpaired electrons. It is diamagnetic.$4$. In $[Ni(CN)_4]^{2-}$,$Ni$ is in the $+2$ oxidation state $(3d^8)$. $CN^-$ is a strong field ligand,causing pairing,resulting in $0$ unpaired electrons. It is diamagnetic.Therefore,$[Ni(H_2O)_6]^{2+}$ is the paramagnetic species.

Similar Questions

The magnetic moment of a metal ion from the first transition series is $2.83 \, BM$. How many unpaired electrons are present in this ion?

$[Co(NH_3)_4Cl_2]NO_2$ and $[Co(NH_3)_4Cl.NO_2]Cl$ are $........$ isomers.

Write all the geometrical isomers of $[Pt(NH_3)(Br)(Cl)(Py)]$ and determine how many of these will exhibit optical isomerism.

The formula for calculating 'spin only' magnetic moment is

Vedclass Test Series

Exam Paper Generator

Online Exam Module