(B) The magnetic moment $\mu$ is given by the formula $\mu = \sqrt{n(n+2)} \, BM$,where $n$ is the number of unpaired electrons.Given $\mu = 2.83 \, B

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(B) The magnetic moment $\mu$ is given by the formula $\mu = \sqrt{n(n+2)} \, BM$,where $n$ is the number of unpaired electrons.Given $\mu = 2.83 \, BM$.$2.83 = \sqrt{n(n+2)}$Squaring both sides: $8 = n(n+2)$$n^2 + 2n - 8 = 0$$(n+4)(n-2) = 0$Since $n$ must be positive,$n = 2$.Thus,there are $2$ unpaired electrons present in the ion.