0.5 , M ammonium benzoate is hydrolysed to 0. | vedclass

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(C) For the salt hydrolysis of ammonium benzoate $(C_6H_5COONH_4)$,the degree of hydrolysis is given as $\alpha = 0.25 \% = 0.0025$.Concentration $C =

Vedclass · Accepted Answer

$3.125 	imes 10^{-6}$

Vedclass · Answer

(C) For the salt hydrolysis of ammonium benzoate $(C_6H_5COONH_4)$,the degree of hydrolysis is given as $\alpha = 0.25 \% = 0.0025$.Concentration $C = 0.5 \, M$.The formula for the hydrolysis constant $(K_h)$ for a salt of a weak acid and a weak base is $K_h = \frac{\alpha^2 C}{1 - \alpha}$.Since $\alpha$ is very small $(0.0025 \ll 1)$,we can approximate $1 - \alpha \approx 1$.Thus,$K_h = \alpha^2 C$.Substituting the values: $K_h = (0.0025)^2 	imes 0.5$.$K_h = (6.25 	imes 10^{-6}) 	imes 0.5 = 3.125 	imes 10^{-6}$.

$0.5 \, M$ ammonium benzoate is hydrolysed to $0.25 \%$ percent,hence its hydrolysis constant is

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