Which of the following compounds will exhibit | vedclass

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(C) For a compound to exhibit geometrical isomerism,each carbon atom of the double bond must be attached to two different groups.In $1$-Phenylpropene

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$1$-Phenylpropene

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(C) For a compound to exhibit geometrical isomerism,each carbon atom of the double bond must be attached to two different groups.In $1$-Phenylpropene $(C_6H_5-CH=CH-CH_3)$,the first carbon of the double bond is attached to a phenyl group and a hydrogen atom,while the second carbon is attached to a methyl group and a hydrogen atom.Since both carbons have two different groups attached,it exhibits geometrical isomerism (cis and trans forms).In But$-1-$ene,Propene,and $2$-Methylbut$-2-$ene,at least one carbon of the double bond is attached to two identical groups (e.g.,two hydrogen atoms or two methyl groups),so they do not show geometrical isomerism.

Which of the following compounds will exhibit geometrical isomerism?

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