According to the E and Z nomenclature,which i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In the $E-Z$ system,the priority of groups attached to each carbon of the double bond is determined by the Cahn-Ingold-Prelog $(CIP)$ rules based

Vedclass · Accepted Answer

$1-$chloro$-1-$propen$-1-$ol

Vedclass · Answer

(A) In the $E-Z$ system,the priority of groups attached to each carbon of the double bond is determined by the Cahn-Ingold-Prelog $(CIP)$ rules based on atomic number.If the groups of higher priority are on opposite sides of the double bond,the isomer is designated as $E$ (from the German word 'entgegen',meaning opposite).If the groups of higher priority are on the same side,the isomer is designated as $Z$ (from the German word 'zusammen',meaning together).In option $A$,the structure is $1$-chloro-$1$-propen-$1$-ol. On the left carbon,$Cl$ (atomic number $17$) has higher priority than $H$ (atomic number $1$). On the right carbon,$OH$ (oxygen,atomic number $8$) has higher priority than $CH_3$ (carbon,atomic number $6$). Since the higher priority groups ($Cl$ and $OH$) are on opposite sides,this is the $E$ isomer.

According to the $E$ and $Z$ nomenclature,which isomer is $E$?

Similar Questions

How many geometrical isomers are possible for $1,4$-dimethylcyclohexane?

Which of the following compounds does not exhibit geometrical isomerism?

Which compound does not show geometrical isomerism?

Which of the following compounds will show geometrical isomerism?

Identify the $E$ and $Z$ configurations for the following structures.

Vedclass Test Series

Exam Paper Generator

Online Exam Module