Identify the E and Z configurations for the f | vedclass

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(C) To assign $E$ and $Z$ configurations,we use the Cahn-Ingold-Prelog $(CIP)$ priority rules based on atomic number.$1$. In structure $1$ (pent$-2-$e

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$1-Z, 2-Z, 3-E, 4-E$

Vedclass · Answer

(C) To assign $E$ and $Z$ configurations,we use the Cahn-Ingold-Prelog $(CIP)$ priority rules based on atomic number.$1$. In structure $1$ (pent$-2-$ene),the higher priority groups ($-CH_3$ and $-CH_2CH_3$) are on the same side of the double bond,so it is $Z$.$2$. In structure $2$ ($2$-methylpent$-2-$ene),the higher priority groups ($-CH_3$ and $-CH_2CH_3$) are on the same side of the double bond,so it is $Z$.$3$. In structure $3$ (stilbene),the higher priority groups (phenyl rings) are on opposite sides of the double bond,so it is $E$.$4$. In structure $4$ ($1$-bromo$-1-$chloroprop$-1-$ene),the higher priority groups ($-Cl$ and $-CH_3$) are on opposite sides of the double bond,so it is $E$.Therefore,the configuration is $1-Z, 2-Z, 3-E, 4-E$.

Identify the $E$ and $Z$ configurations for the following structures.

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