The number of geometrical isomers for CH_3CH= | vedclass

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Question

(A) The given compound is $CH_3-CH=CH-CH=CH-CH_2CH_3$.This is an unsymmetrical polyene with $n = 2$ double bonds capable of showing geometrical isomer

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(A) The given compound is $CH_3-CH=CH-CH=CH-CH_2CH_3$.This is an unsymmetrical polyene with $n = 2$ double bonds capable of showing geometrical isomerism.The formula for the number of geometrical isomers for an unsymmetrical alkene is $2^n$,where $n$ is the number of double bonds that can show geometrical isomerism.Here,$n = 2$.Therefore,the number of geometrical isomers = $2^2 = 4$.The four isomers are: $(cis, cis)$,$(cis, trans)$,$(trans, cis)$,and $(trans, trans)$.

The number of geometrical isomers for $CH_3CH=CH-CH=CH-C_2H_5$ is .......

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