Which of the following will undergo S_{N}2 re | vedclass

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(D) The rate of $S_{N}2$ reaction depends on the steric hindrance around the carbon atom attached to the leaving group. The order of reactivity for $S

Vedclass · Accepted Answer

$(CH_{3})_{2}CH-CH_{2}CH_{2}CH_{2}I$

Vedclass · Answer

(D) The rate of $S_{N}2$ reaction depends on the steric hindrance around the carbon atom attached to the leaving group. The order of reactivity for $S_{N}2$ is: $	ext{Primary} > 	ext{Secondary} > 	ext{Tertiary}$.Additionally,the nature of the leaving group affects the rate: $I^{-} > Cl^{-}$.Comparing the options:$(A)$ $(CH_{3})_{3}C-CH_{2}I$ is a primary alkyl halide with steric hindrance at the $\beta$-carbon.$(B)$ $(CH_{3})_{3}C-Cl$ is a tertiary alkyl halide,which is very slow for $S_{N}2$.$(C)$ $(CH_{3})_{2}CH-I$ is a secondary alkyl halide.$(D)$ $(CH_{3})_{2}CH-CH_{2}CH_{2}CH_{2}I$ is a primary alkyl halide with less steric hindrance compared to $(A)$.Therefore,$(CH_{3})_{2}CH-CH_{2}CH_{2}CH_{2}I$ is the most reactive towards $S_{N}2$ due to being a primary alkyl halide with the best leaving group $(I^{-})$ and minimal steric hindrance at the $\alpha$-carbon.

Which of the following will undergo $S_{N}2$ reaction most rapidly?

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Correct statement is:

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