In a ccp structure of X atoms,Y atoms occupy | vedclass

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(B) In a $ccp$ structure,the number of $X$ atoms per unit cell is $4$. The number of octahedral voids is equal to the number of atoms,which is $4$. $Y

Vedclass · Accepted Answer

$X_3YZ_2$

Vedclass · Answer

(B) In a $ccp$ structure,the number of $X$ atoms per unit cell is $4$. The number of octahedral voids is equal to the number of atoms,which is $4$. $Y$ atoms occupy half of the octahedral voids,so the number of $Y$ atoms is $4 	imes \frac{1}{2} = 2$. If one $X$ atom is replaced by $Z$,the remaining $X$ atoms = $4 - 1 = 3$. If one $Y$ atom is replaced by $Z$,the remaining $Y$ atoms = $2 - 1 = 1$. The total number of $Z$ atoms introduced is $1 + 1 = 2$. Thus,the ratio of $X:Y:Z$ is $3:1:2$. The molecular formula is $X_3YZ_2$.

In a $ccp$ structure of $X$ atoms,$Y$ atoms occupy half of the octahedral voids. If one $X$ atom and one $Y$ atom in each unit cell are replaced by a $Z$ atom,the molecular formula of the solid will be:

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