In chrysoberyl,a compound containing berylliu | vedclass

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(A) Let the number of oxide ions $(O^{2-})$ in the $ccp$ structure be $N$.Number of octahedral voids = $N$.Number of tetrahedral voids = $2N$.Given th

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$BeAlO_{4}$

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(A) Let the number of oxide ions $(O^{2-})$ in the $ccp$ structure be $N$.Number of octahedral voids = $N$.Number of tetrahedral voids = $2N$.Given that $Al^{3+}$ ions occupy $\frac{1}{4}$ of the octahedral voids,so number of $Al^{3+} = \frac{1}{4} 	imes N = \frac{N}{4}$.Given that $Be^{2+}$ ions occupy $\frac{1}{8}$ of the tetrahedral voids,so number of $Be^{2+} = \frac{1}{8} 	imes 2N = \frac{N}{4}$.The ratio of $Be : Al : O$ is $\frac{N}{4} : \frac{N}{4} : N$.Multiplying by $4$,we get the ratio $1 : 1 : 4$.Therefore,the formula of the compound is $BeAlO_{4}$.

In chrysoberyl,a compound containing beryllium,aluminium and oxygen,oxide ions form a cubic close-packed structure. Aluminium ions occupy $\frac{1}{4}$ of the octahedral voids and beryllium ions occupy $\frac{1}{8}$ of the tetrahedral voids. The formula of the compound is

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