The reaction of glucose with CH_3OH in the pr | vedclass

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(C) Glucose reacts with methanol $(CH_3OH)$ in the presence of dry $HCl$ to form methyl glucoside. This reaction involves the formation of an acetal f

Vedclass · Accepted Answer

cyclic structure

Vedclass · Answer

(C) Glucose reacts with methanol $(CH_3OH)$ in the presence of dry $HCl$ to form methyl glucoside. This reaction involves the formation of an acetal from the hemiacetal structure of glucose. Since glucose forms a glycoside,it confirms that glucose exists in a cyclic structure (hemiacetal form) rather than an open-chain aldehyde form.

The reaction of glucose with $CH_3OH$ in the presence of dry $HCl$ yields methyl glucoside,which indicates the presence of a/an .... in glucose.

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