For an amino acid,the ionization constant for | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The isoelectric point $(pI)$ of an amino acid is the $pH$ at which the molecule carries no net electric charge.For a neutral amino acid,the $pI$ i

Vedclass · Accepted Answer

$5.97$

Vedclass · Answer

(A) The isoelectric point $(pI)$ of an amino acid is the $pH$ at which the molecule carries no net electric charge.For a neutral amino acid,the $pI$ is calculated as the average of the $pK_a$ values of the two ionizable groups:$pI = \frac{pK_{a_1} + pK_{a_2}}{2}$Given $pK_{a_1} = 2.34$ and $pK_{a_2} = 9.6$:$pI = \frac{2.34 + 9.6}{2} = \frac{11.94}{2} = 5.97$Therefore,the isoelectric point is $5.97$.

For an amino acid,the ionization constant for the carboxyl group is $pK_{a_1} = 2.34$ and for the ammonium ion is $pK_{a_2} = 9.6$. At what $pH$ will the isoelectric point of the amino acid be?

Similar Questions

Which of the following amino acids contains the $HN=C(NH_2)-$ linkage?

The monomer of a polypeptide is........

The functional group which is found in amino acid is

The number of essential amino acids in man is

Glycine may be classed as all of the following except

Vedclass Test Series

Exam Paper Generator

Online Exam Module