What is the decreasing order of Lewis acid st | vedclass

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(B) The Lewis acid strength of boron halides depends on the extent of back-bonding between the lone pair of the halogen and the empty $p$-orbital of b

Vedclass · Accepted Answer

$BBr_3 > BCl_3 > BF_3$

Vedclass · Answer

(B) The Lewis acid strength of boron halides depends on the extent of back-bonding between the lone pair of the halogen and the empty $p$-orbital of boron. In $BF_3$,the $2p-2p$ back-bonding is most effective due to the small size of fluorine,which significantly reduces the electron deficiency of boron. As the size of the halogen increases from $F$ to $I$,the effectiveness of back-bonding decreases ($2p-3p$ in $BCl_3$,$2p-4p$ in $BBr_3$). Therefore,the electron deficiency of boron increases from $BF_3$ to $BI_3$,making $BBr_3$ a stronger Lewis acid than $BCl_3$,which is stronger than $BF_3$. The correct order is $BBr_3 > BCl_3 > BF_3$.

What is the decreasing order of Lewis acid strength of boron halides?

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