The dissolution of Al(OH)_3 by a solution of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $Al(OH)_3$ is an amphoteric hydroxide that dissolves in a strong base like $NaOH$ to form a soluble complex.In aqueous solution,the aluminum ion m

Vedclass · Accepted Answer

$[Al(H_2O)_2(OH)_4]^-$

Vedclass · Answer

(C) $Al(OH)_3$ is an amphoteric hydroxide that dissolves in a strong base like $NaOH$ to form a soluble complex.In aqueous solution,the aluminum ion maintains its coordination number of $6$.Therefore,the reaction is: $Al(OH)_3(s) + OH^-(aq) + 2H_2O(l) 	o [Al(OH)_4(H_2O)_2]^-(aq)$.Thus,the correct species formed is $[Al(H_2O)_2(OH)_4]^-$,which is option $C$.

The dissolution of $Al(OH)_3$ by a solution of $NaOH$ results in the formation of

Similar Questions

The number of three-centre two-electron $(3c-2e)$ bonds in a molecule of diborane $(B_2H_6)$ is

Which of the following properties describes the diagonal relationship between boron and silicon?

The compound$(s)$ which react$(s)$ with $NH_3$ to give boron nitride $(BN)$ is(are):

Which of the following structures does not represent the structure of the substance given in the brackets?

Give uses of boron and its compounds.

Vedclass Test Series

Exam Paper Generator

Online Exam Module