$PbF_4$ and $PbCl_4$ exist,while $PbBr_4$ and $PbI_4$ do not. The reason for this is .......
- ALarge size of $Br$ and $I$
- BStrong oxidizing nature of $Pb^{4+}$
- CStrong reducing nature of $Pb^{4+}$
- DLow electronegativity of $Br^-$ and $I^-$
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