A metal X on heating in a stream of nitrogen | vedclass

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Question

(B) The metal $X$ is Magnesium $(Mg)$.When $Mg$ is heated in a stream of nitrogen gas,it forms Magnesium nitride $(Mg_3N_2)$: $3Mg + N_2 \rightarrow M

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$Mg_3N_2$

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(B) The metal $X$ is Magnesium $(Mg)$.When $Mg$ is heated in a stream of nitrogen gas,it forms Magnesium nitride $(Mg_3N_2)$: $3Mg + N_2 \rightarrow Mg_3N_2$ $(Y)$.When $Mg_3N_2$ reacts with water,it produces ammonia gas $(NH_3)$: $Mg_3N_2 + 6H_2O \rightarrow 3Mg(OH)_2 + 2NH_3 \uparrow$.Ammonia gas reacts with $CuSO_4$ solution to form a deep blue complex $[Cu(NH_3)_4]^{2+}$,which confirms the presence of $NH_3$.

$A$ metal $X$ on heating in a stream of nitrogen gas gives $Y$. $Y$ on reaction with $H_2O$ gives a colorless gas which turns $CuSO_4$ solution blue. What is $Y$?

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$A$ $\xrightarrow{\Delta } B + C_{(gas)}$ $\xrightarrow{Ca(OH)_2} D_{(milky)} + H_2O$ $\xrightarrow{C_{(gas)}} E$
Then the incorrect statement is:

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