An organic compound with the molecular formul | vedclass

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Question

(B) $1$. The molecular formula $C_3H_6O$ corresponds to a degree of unsaturation of $1$ $(3 - 6/2 + 1 = 1)$.$2$. The compound does not react with $2,4

Vedclass · Accepted Answer

$CH_2=CH-OCH_3$

Vedclass · Answer

(B) $1$. The molecular formula $C_3H_6O$ corresponds to a degree of unsaturation of $1$ $(3 - 6/2 + 1 = 1)$.$2$. The compound does not react with $2,4-DNP$,which indicates the absence of a carbonyl group (aldehyde or ketone).$3$. The compound does not react with sodium metal,which indicates the absence of an active hydrogen atom (like in alcohols or phenols).$4$. Given these conditions,the compound must be an ether with a double bond (unsaturated ether).$5$. Among the options,$CH_2=CH-OCH_3$ (methoxyethene) fits the molecular formula $C_3H_6O$,lacks a carbonyl group,and lacks an active hydrogen atom.

An organic compound with the molecular formula $C_3H_6O$ does not give a precipitate with $2,4-$dinitrophenylhydrazine $(2,4-DNP)$ and does not react with sodium metal. What is this compound?

Similar Questions

Which product is formed when sodium phenoxide is heated with ethyl iodide?

The major products formed in the reaction of $t$-butyl methyl ether with $HI$ are

$Ph - \mathop O\limits^{18} - CH_3 \xrightarrow{conc. HI} \text{products}$

Methylphenyl ether can be obtained by reacting

Assertion : Iodide ion combines with smaller group to avoid steric hindrance.
Reason : With $HI$,anisole gives iodobenzene and methyl alcohol.

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