$1 \ mol$ of compound $N_2H_4$ loses $10 \ mol$ of electrons to form a new compound $Y$. Assuming all nitrogen atoms are present in compound $Y$,what is the oxidation state of $N$ in compound $Y$?
- A$-1$
- B$-3$
- C$+3$
- D$+5$
Explore More
Similar Questions
The oxidation states of sulfur atoms and the number of $S-OH$ bonds in Peroxydisulfuric acid are respectively:
Identify the species in which the central atom has an oxidation state of $+6$.
Medium
View SolutionThe oxidation states of $S$ in peroxodisulphuric acid $(H_{2}S_{2}O_{8})$ and sodium tetrathionate $(Na_{2}S_{4}O_{6})$ are respectively:
Medium
View SolutionWhat is the oxidation number of sulfur in $Na_2S_4O_6$?
Medium
View SolutionThe oxidation number of sulphur in $S_2O_3^{2-}$ is:
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo